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What is the identity of the element X in the following ions?

(a) x²⁺, a cation that has 38 electrons
(b) X, an anion that has 35 electrons

User Hndr
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1 Answer

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Final answer:

The element X in both ions is Krypton (Kr) with a valency of 2. It can form two covalent bonds.

Step-by-step explanation:

In order to determine the identity of the element X in the given ions, we need to look at the number of electrons and the charge of the ions.

(a) The cation x²⁺ has 38 electrons. We can determine the atomic number by subtracting the charge from the number of electrons. In this case, 38 - 2 = 36. Looking at the periodic table, we find that the element with 36 protons is Krypton (Kr).

(b) The anion X with 35 electrons has a charge of 1-. To determine the atomic number, we add the charge to the number of electrons. In this case, 35 + 1 = 36. Again, referring to the periodic table, we find that the element with 36 protons is Krypton (Kr).

(c) The valency of element X in both cases is 2.

(d) The number of covalent bonds in the molecule depends on the valency of the element X. Since X has a valency of 2, it can form 2 covalent bonds.

(e) Based on the information given, we can suggest the element X to be Krypton (Kr).

User Nrudnyk
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