Question

if stiffness is constant, evaluate the work done, in j if l0= 3cm, l1=6cm, l2= 20 cm and the stiffness is k =3x10^4 n/m

Answer 1

The work done by the spring force is 0.063 J.

Step-by-step explanation:

To find the work done, we can use the equation for the work done by a spring force: W = 0.5k(x^2 - x0^2), where k is the spring constant, x is the final stretch of the spring, and x0 is the initial stretch of the spring.

In this case, x1 = 6 cm and x0 = 3 cm. Plugging in the values, we get W = 0.5(3x10^4 N/m)((0.06 m)^2 - (0.03 m)^2). Solving this equation, we find that the work done is 0.063 J.