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Write the net ionic equation for the reaction between barium nitrate and chromium(iii) sulfate.

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Final answer:

The net ionic equation for the reaction between barium nitrate and chromium(III) sulfate is Ba2+(aq) + 3SO4^2-(aq) → BaSO4(s).

Step-by-step explanation:

The net ionic equation for the reaction between barium nitrate (Ba(NO3)2) and chromium(III) sulfate (Cr2(SO4)3) can be determined by writing the balanced molecular equation, followed by writing the complete ionic equation, and finally identifying the spectator ions to write the net ionic equation.

The balanced molecular equation is:

Ba(NO3)2(aq) + Cr2(SO4)3(aq) → BaSO4(s) + Cr(NO3)3(aq)

The complete ionic equation can be written by breaking down the soluble ionic compounds into their constituent ions:

Ba2+(aq) + 2NO3-(aq) + 2Cr3+(aq) + 3SO42-(aq) → BaSO4(s) + 2Cr3+(aq) + 6NO3-(aq)

From the complete ionic equation, we can see that the spectator ions (ions that appear on both sides of the equation and do not participate in the reaction) are 2Cr3+(aq) and 6NO3-(aq). The net ionic equation is obtained by removing the spectator ions:

Ba2+(aq) + 3SO42-(aq) → BaSO4(s)

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