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Calculate Kp for the following reaction: H₂(g) + CO₂(g) ⇌ H₂O(g) + CO(g). Given that Kc = 45.0 at 250 °C,

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Final answer:

To calculate Kp for the reaction H₂(g) + CO₂(g) ⇌ H₂O(g) + CO(g), we can use the equation Kp = Kc * (RT)^Δn. Given that Kc = 45.0 at 250°C, the value of Kp for the reaction is 1926.9.

Step-by-step explanation:

To calculate Kp for the reaction H₂(g) + CO₂(g) ⇌ H₂O(g) + CO(g), we can use the equation:

Kp = Kc * (RT)Δn

where Kc is the equilibrium constant at a given temperature, R is the ideal gas constant, T is the temperature in Kelvin, and Δn is the change in the number of moles of gaseous products minus reactants.

In this reaction, Δn = (1+1) - (1+1) = 0.

Given that Kc = 45.0 at 250 °C, we can convert the temperature to Kelvin: 250 + 273.15 = 523.15 K.

Plugging in the values into the equation, we get:

Kp = 45.0 * (0.0821 * 523.15)0 = 1926.9

Therefore, the value of Kp for the reaction is 1926.9.

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