Question

A mass of 1.5 kg of air at 120 kPa and 24°C undergoes a process during which the pressure remains constant. The final temperature of the air is 60°C. What is the final volume of the air?

1) Cannot be determined
2) 2.5 L
3) 3.0 L
4) 3.5 L

Answer 1

To find the final volume of the air, we can use the ideal gas law equation. Given the initial mass of the air, we calculate the number of moles using the molar mass of air. Plugging in the values into the equation, we find that the final volume of the air is approximately 3.08 L.

Step-by-step explanation:

To find the final volume of the air, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Since the pressure remains constant, we can rearrange the equation to solve for the final volume: V = nRT/P. Given that the initial mass of the air is 1.5 kg, we can use the molar mass of air to calculate the number of moles. The molar mass of air is approximately 28.97 g/mol. Thus, the number of moles (n) is 1500 g / 28.97 g/mol = 51.77 mol. Plugging in the values into the equation, we get V = (51.77 mol)(8.314 J/mol·K)(333 K)/120,000 Pa = 3.08 L. Therefore, the final volume of the air is approximately 3.08 L.