Final answer:
To determine the concentration of HCl, we use the titration formula M1V1 = M2V2, which results in the concentration of HCl being 0.119 M.
Step-by-step explanation:
The question involves a titration of sodium hydroxide (NaOH) and hydrochloric acid (HCl). We're given that 25.0 cm3 of 0.1 M NaOH is needed to neutralize 21.0 cm3 of HCl. To find the molarity (M) of HCl, we use the titration formula: M1V1 = M2V2, where M1 and V1 are the molarity and volume of HCl, and M2 and V2 are the molarity and volume of NaOH. Since the reaction ratio of HCl to NaOH is 1:1, we can calculate M1 (the molarity of HCl) as follows:
(0.1 M) * (25.0 cm3) = M1 * (21.0 cm3)
M1 = (0.1 M * 25.0 cm3) / 21.0 cm3
M1 = 0.1190 M
Therefore, the concentration of the hydrochloric acid is 0.119 M.