Final answer:
The value of acceleration at t=12s is 1.2 m/s^2.
Step-by-step explanation:
To find the value of acceleration at t=12s, we can use the given position function, which is in the form x(t) = xo + vot + 1/2at^2, where xo is the initial position, vo is the initial velocity, and a is the acceleration.
In this case, xo = 0m, vo = 0m/s, t = 12s, and we need to find a. Plugging in these values into the position function, we get x(12) = 1/2a(12)^2
Simplifying the equation, we have 172.8m = 144a. Dividing both sides by 144, we get a = 172.8m/144 = 1.2m/s^2.