Answer:
Below
Explanation:
Look for .9300 on the z-score table
= z-score = + 1.48
1.48 standard deciations = 1.48 * 15 = 22.2
110 + 22.2 = 132.2
132.2 is 1.48 standard deviations above the mean and is .9308 (93.08%)
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