Final answer:
The parametric equations for the line parallel to the given line can be expressed as x = -6 + (1/2)t, y = 2 + (1/3)t, and z = 3 + t.
Step-by-step explanation:
To find the parametric equations for a line parallel to the line 1/2x = 1/3y = z/1 and passing through the point (-6, 2, 3), we can use the direction vector of the given line. The direction vector is given by the coefficients of x, y, and z in the equation of the line, which are 1/2, 1/3, and 1.
Let's use t as the parameter. The parametric equations for the line are:
x = -6 + (1/2)t
y = 2 + (1/3)t
z = 3 + t