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Find parametric equations for the line. (Use the parameter t.) The line through (-6, 2, 3) and parallel to the line 1/2x = 1/3y = z/1?

User Iwolf
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Final answer:

The parametric equations for the line parallel to the given line can be expressed as x = -6 + (1/2)t, y = 2 + (1/3)t, and z = 3 + t.

Step-by-step explanation:

To find the parametric equations for a line parallel to the line 1/2x = 1/3y = z/1 and passing through the point (-6, 2, 3), we can use the direction vector of the given line. The direction vector is given by the coefficients of x, y, and z in the equation of the line, which are 1/2, 1/3, and 1.



Let's use t as the parameter. The parametric equations for the line are:



x = -6 + (1/2)t

y = 2 + (1/3)t

z = 3 + t

User Flavius Stef
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