Answer: Location of T' on the coordinate axis will be (16,7).
T (6,4) → T' (16,7).
Explanation:
coordinate vertices of points in rectangle JKLM are:
J (-8,-8)
K (-4,-8)
L (-4,-5)
M (-8,-5)
and coordinate vertices of points in rectangle J'K'L'M' are:
J' (2,-5)
K' (6,-5)
L' (6,-2)
M' (2,-2)
coordinate vertices of points in Quadrilateral STUV are:
S (1,4)
T (6,4)
U (4,6)
V (2,6)
transformation in coordinate vertices from rectangle JKLM to rectangle J'K'L'M' is:
J (-8,-8) → J' (2,-5)
⇒ along x axis -8 → 2 which means that rectangle is shifting towards right by 10 units.
and along y axis -8 → -5 which means that the rectangle is shifting upwards by 3 units.
similarly for
K (-4,-8) → K' (6,-5)
⇒ along x axis -4 → 6 which means that rectangle is shifting towards right by 10 units.
and along y axis -8 → -5 which means that the rectangle is shifting upwards by 3 units.
L (-4,-5) → L' (6,-2)
⇒ along x axis -4 → 6 which means that rectangle is shifting towards right by 10 units.
and along y axis -5 → -2 which means that the rectangle is shifting upwards by 3 units.
M (-8,-5) → M' (2,-2)
⇒ along x axis -8 → 2 which means that rectangle is shifting towards right by 10 units.
and along y axis -5 → -2 which means that the rectangle is shifting upwards by 3 units.
So, the location of T' of the Quadrilateral S'T'U'V' on the coordinate plane will be:
along x axis the Quadrilateral will shift towards right by 10 units
So, 6 → 6+10=16
and along y axis the Quadrilateral will shift upwards by 3 units
So, 4 → 4+3=7
⇒ T (6,4) → T' (16,7).
Explanation: