Question

I need help with this problem. Can anyone help

Answer 1

The graph is a piecewise linear function with two segments: y=x for x<50 and y=80 for x>50. The function intersects y=50 at x=50, y=80 at x=88 and y=0 at x=-40.

The graph shows a piecewise linear function with two segments. The first segment has a slope of 1 and a y-intercept of 0, so it is a line equation of
`$y=x$`. The second segment has a slope of 0 and a y-intercept of 80, so it is a line equation of
`$y=80$`.

To answer the parts (a)-(f), we need to find the x-values where the graph intersects the lines
`$y=50$, $y=80$,` and
`$y=0$`.

(a) The graph intersects the line y=50 at x=50. So, the solution to f(x)=50 is x=boxed{50}.

(b) The graph intersects the line
`$y=80$ at $x=88$`. So, the solution to f{x)=80 is x=boxed{88}.

(c) The graph intersects the line y=0 at x=-40. So, the solution to f(x)=0 is x=boxed{-40}.

(d) The graph is above the line y=50 between x=50 and x=88. So, the solution to f(x)>50 is xinboxed{(50,88)}.

(e) The graph is below or equal to the line y=80 between x=-40 and x=88. So, the solution to f(x)80 is xinboxed{[-40,88]}.

(f) The graph is between the lines y=0 and y=80 between x=-40 and x=88. So, the solution to 0<f(x)<80 is xinboxed{(-40,88)}.