Question

A motorcycle slows down at -6.42m/s ^2

It takes 2.85s before the motorcycle comes to a complete stop.

What was the initial velocity of the motorcycle?

Answer 1

18.295 m/s

Step-by-step explanation:

Vi = initial velocity, Vf = final velocity, t = time, and a = acceleration

From the question, we know that a = -6.42, t = 2.85, and Vf = 0 (Vf = 0 because the motorcycle "comes to a complete stop")

With this info, we can see that we can substitute this into the kinematic equation Vf = Vi + at

First, rearrange the equation to solve for Vi:

Vi = Vf - at

Then plug in your known values:

Vi = 0 - (-6.42)(2.85)

Then solve:

Vi = 18.295 m/s