Question

Please solve this question given in the picture.​

Answer 1

`\sf\\i.\ \angle ADE=\angle BCE=120^o\ \ \ [\textsf{Corresponding angles are equal.}]\\or,\ y=120^o\\\\ii.\ \angle AED=\angle DAE=x\ \ \ [\textsf{Base angles of isosceles triangle are equal.}]\\\\iii.\ \angle AED+\angle DAE+\angle EDA=180^o \ \ \ [\textsf{Sum of angles of triangle is 180}^o.]\\or,\ x+x+y=180^o\\or,\ 2x+120^o=180^o\\or,\ 2x=60^o\\or,\ x=30^o`