Question

What are the real zeros for this?

Answer 1

The real zeros of the function
`h(x) = 3(x^2-4)(x+3)^2(x-3)` are:

x = -3, -2, 2, and 3.

How to find the real zeros of the function

To find the real zeros of the function
`h(x) = 3(x^2-4)(x+3)^2(x-3)` , set the function equal to zero and solve for x.

Setting h(x) = 0, we have:

3(x²-4)(x+3)²(x-3) = 0

Now, we can set each factor equal to zero and solve for x:

x² - 4 = 0:

Solving this quadratic equation

x² = 4

Taking the square root of both sides

x = ±2

(x+3)² = 0:

Solving this equation

x+3 = 0

x = -3

(x-3) = 0:

Solving this equation

x = 3

Therefore, the real zeros of the function
`h(x) = 3(x^2-4)(x+3)^2(x-3)` are:

x = -3, -2, 2, and 3.