Using the laws of circuit theory: RT = 8.6 kΩ, IT = 1.044 mA, V1 = 4.91 V, V2 = 1.25 V and V3 = 2.83 V
Here are the solutions to the circuit problem in the image, using the laws of circuit theory:
Total resistance (RT):
The total resistance in a series circuit is the sum of the individual resistances. Therefore,
RT = R1 + R2 + R3
= 4700 Ω + 1.2 kΩ + 2700 Ω
= 8600 Ω.
Total current (IT):
Ohm's law states that the current through a resistor is equal to the voltage across the resistor divided by the resistance. In this case, the voltage across the entire circuit is VT = 9 V. Therefore, the total current is IT = VT / RT
= 9 V / 8600 Ω
= 0.001044 A.
Voltage across each resistor:
The voltage across each resistor is equal to the current through the resistor multiplied by the resistance. Therefore:
V1 = IT * R1 = 0.001044 A * 4700 Ω = 4.91 V
V2 = IT * R2 = 0.001044 A * 1200 Ω = 1.25 V
V3 = IT * R3 = 0.001044 A * 2700 Ω = 2.83 V