Final answer:
To have $10,000 in a bank account after ten years with 10% interest compounded annually, you would need to deposit approximately $3,855.43 initially.
Step-by-step explanation:
To determine how much money needs to be deposited into a bank account with 10% interest compounded annually to have $10,000 in ten years, we use the formula for compound interest:
P = A / (1 + r/n)^(nt)
Where:
- P is the principal amount (the initial amount of money)
- A is the future value of the investment/loan, including interest
- r is the annual interest rate (decimal)
- n is the number of times that interest is compounded per year
- t is the number of years the money is invested or borrowed for
In this case, the future value A is $10,000, the annual interest rate r is 10% or 0.10, the interest is compounded annually so n is 1, and the time t is 10 years.
Plugging these values into our formula gives us:
P = $10,000 / (1 + 0.10/1)^(1*10)
P = $10,000 / (1.10)^10
P = $10,000 / 2.59374
P ≈ $3,855.43
Therefore, you would need to initially deposit approximately $3,855.43 to have $10,000 in the account after ten years, with 10% interest compounded annually.