Final answer:
The final solution would have a mass of 62.5g.
Step-by-step explanation:
In this question, you are given that 32g of copper sulphate dissolves in 100g of water at 20 degrees. You are asked to find out what would happen if 20g of copper sulphate is dissolved in 100g of water at 20 degrees.
Since the ratio of copper sulphate to water is constant, you can use this ratio to find the answer. The ratio of copper sulphate to water is 32g/100g. So, if you have 20g of copper sulphate, you can set up a proportion:
32g/100g = 20g/x
Cross-multiply and solve for x:
x = (20g * 100g) / 32g
x = 62.5g
Therefore, if you have 20g of copper sulphate and 100g of water at 20 degrees, the copper sulphate would dissolve and the final solution would have a mass of 62.5g.