Question

The swimming pool is open when the high temperature is higher than 20°C. Lainey tried to swim on Monday and Thursday (which was 3 days later). The pool was open on Monday, but it was closed on Thursday. The high temperature was 30°C on Monday, but decreased at a constant rate in the next 3 days. Will the pool be open on Thursday?

1) True
2) False

Answer 1

The temperature on Monday was 30°C and dropped at a constant rate, causing the pool to close by Thursday. By calculating, it's deduced that the high temperature was below 20°C on Thursday, so the pool would be closed, making the statement false.

Step-by-step explanation:

The question involves determining whether the swimming pool will be open on Thursday based on the temperature changes occurring from Monday to Thursday. On Monday, the high temperature was 30°C, and the pool's requirement is that the high temperature must be over 20°C. Since the temperature decreased at a constant rate over 3 days and the pool was closed on Thursday, we can infer that the temperature dropped below this threshold.

Let's calculate the rate of temperature decrease. The high was 30°C on Monday, and by conditions given for the pool being open, it must be higher than 20°C. With a 3-day interval for the temperature to drop, the temperature must decline by more than (30-20) °C over 3 days to result in closure, which is more than ⅔°C drop per day. This means that by Thursday, the temperature would be 30°C - 3 days * (⅔°C/day) = 30°C - more than 10°C, which would be less than 20°C. Thus, the pool would be closed on Thursday due to low temperature, making the statement False.