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If 0.676j of heat is added to 0.7737g of water, how much will the temperature increase?

User JayTee
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Final answer:

To calculate the temperature increase, use the formula: Q = mcΔT, where Q is the heat added, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Step-by-step explanation:

To calculate the temperature increase, you need to use the formula: Q = mcΔT, where Q is the heat added, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Since the specific heat capacity of water is 4.184 J/g°C, the mass of the water is 0.7737g, and the heat added is 0.676j, we can calculate the temperature increase as follows:

0.676j = (0.7737g)(4.184 J/g°C) * ΔT

ΔT = 0.676j / {(0.7737g)(4.184 J/g°C)}

Calculating the above equation will give you the temperature increase in degrees Celsius.

User Cj Anderson
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