Question

A ball is thrown off a clif toward the beach below. The angle that the ball is thrown is 47 degrees below the horizontal with a speed of 25 m/s. An observer times the fall to be 3.5s.

1) How high is the cliff?
2) How far away from the base of the cliff did the ball land?

Answer 1

To calculate the height of the cliff, use the equations for vertical motion and acceleration due to gravity. To calculate the distance away from the base of the cliff, use the equation for horizontal motion. The height of the cliff is 63.3 meters and the ball lands 61.0 meters away from the base of the cliff.

Step-by-step explanation:

To calculate the height of the cliff:

1. Use the equation h = v0yt + 0.5at2 to calculate the initial vertical velocity v0y.
2. Next, use the equation vy = v0y + at to calculate the vertical velocity vy.
3. Finally, use the equation h = v0yt - 0.5gt2 to calculate the height of the cliff, where g is the acceleration due to gravity.

To calculate the distance away from the base of the cliff:

1. Use the equation d = v0xt to calculate the horizontal distance, where v0x is the initial horizontal velocity.

Using the given information, the height of the cliff is 63.3 meters and the ball lands 61.0 meters away from the base of the cliff.