Question

How many mL of 0.060 M CuSO4 solution will you need to make 20 mL of 0.010 M CuSO4 solution?

Option 1: 5 mL
Option 2: 10 mL
Option 3: 20 mL
Option 4: 30 mL

Answer 1

To prepare 20 mL of a 0.010 M CuSO4 solution from a 0.060 M CuSO4 solution, we would need approximately 3.33 mL of the concentrated solution, with the closest available option being 5 mL.

Step-by-step explanation:

The question is asking how to dilute a concentrated CuSO4 solution to a lower concentration while achieving a specific volume of the dilute solution. The calculation is based on the principle of conservation of moles, which can be expressed with the equation C1V1 = C2V2, where C1 and V1 are the concentration and volume of the initial solution, and C2 and V2 are the concentration and volume of the final solution.

To find the volume of the original 0.060 M CuSO4 solution needed to make 20 mL of a 0.010 M CuSO4 solution, we use the equation:

(0.060 M) × (V1) = (0.010 M) × (20 mL)

V1 = × ((0.010 M) × (20 mL)) / (0.060 M)

V1 = 3.33 mL

Since this value does not match any of the available options exactly, we need to select the closest option to the calculated volume, which is Option 1: 5 mL.