Final answer:
The Java statement to calculate 2π + xn + y√4xy, where z, x, and n are ints, is double result = 2 * Math.PI + x * n + y * Math.sqrt(4 * x * y); This uses Math.PI for π and Math.sqrt for the square root.
Step-by-step explanation:
To calculate the value of the formula 2π + xn + y√4xy, given integers z, x, and n in Java, you can use the Math class for π and the square root. Here is a statement that performs the calculation and assigns the result to a variable:
double result = 2 * Math.PI + x * n + y * Math.sqrt(4 * x * y);
This statement assumes that the variables x, y, and n have been previously assigned integer values, and it uses Math.PI to represent π and Math.sqrt to calculate the square root.