Final answer:
The question touches on constructing an 80% confidence interval for a proportion in statistics, which is a Mathematics concept at the College level. The necessary calculation involves using the sample proportion, z-score, and sample size, but specific data is missing to provide a direct answer.
Step-by-step explanation:
The subject of the question is Mathematics, specifically within the topic of statistics, as it involves calculating a confidence interval for a proportion. The student wants to determine the 80% confidence interval for the true proportion of college students with hypertension during finals week, given a 95% confidence interval of (4.0%, ?). To answer such a question, we would require additional information, such as the sample proportion and sample size, or the margin of error. However, since the data to perform this calculation is incomplete, a direct computation cannot be provided.
In general, to compute a confidence interval, one would use the formula p' ± z*(√p'(1-p')/n), where p' is the sample proportion, z is the z-score corresponding to the desired confidence level, and n is the sample size.