Final answer:
The statements can be represented in predicate logic as follows: Every cat is sleeping, Some girl likes David, No one is happy, It is sleeping, She likes David, Every student is happy, Some students are happy, No student complained, Not every student complained.
Step-by-step explanation:
The statements can be represented in predicate logic as follows:
i) Every cat is sleeping
Let C(x) be the statement 'x is a cat'.
Let S(x) be the statement 'x is sleeping'.
The statement can be represented as ∀x (C(x) → S(x)), which reads as 'For every x, if x is a cat, then x is sleeping.'
ii) Some girl likes David
Let G(x) be the statement 'x is a girl'.
Let L(x, y) be the statement 'x likes y'.
The statement can be represented as ∃x (G(x) & L(x, David)), which reads as 'There exists an x, if x is a girl, then x likes David.'
iii) No one is happy
Let H(x) be the statement 'x is happy'.
The statement can be represented as ∀x (~H(x)), which reads as 'For every x, x is not happy.'
iv) It is sleeping
Let S be the statement 'It is sleeping'.
The statement can be represented as S.
v) She likes David
Let L(x, y) be the statement 'x likes y'.
The statement can be represented as L(She, David), which reads as 'She likes David.'
vi) Every student is happy
Let S(x) be the statement 'x is a student'.
Let H(x) be the statement 'x is happy'.
The statement can be represented as ∀x (S(x) → H(x)), which reads as 'For every x, if x is a student, then x is happy.'
vii) Some students are happy
Let S(x) be the statement 'x is a student'.
Let H(x) be the statement 'x is happy'.
The statement can be represented as ∃x (S(x) & H(x)), which reads as 'There exists an x, if x is a student, then x is happy.'
viii) No student complained
Let S(x) be the statement 'x is a student'.
Let C(x) be the statement 'x complained'.
The statement can be represented as ∀x (S(x) → ~C(x)), which reads as 'For every x, if x is a student, then x did not complain.'
ix) Not every student complained
Let S(x) be the statement 'x is a student'.
Let C(x) be the statement 'x complained'.
The statement can be represented as ∃x (S(x) & ~C(x)), which reads as 'There exists an x, if x is a student, then x did not complain.'