49.3k views
0 votes
Set up the matrix for the following system of equations. -5x+4y-z=11 3x-3y-5z=17 -2x-5y+4z=0

User Veer Singh
by
7.6k points

1 Answer

2 votes

Final answer:

To set up the matrix for the given system of linear equations, you create a coefficient matrix with the coefficients of the variables x, y, and z, and a constant matrix with the constants from the right-hand side of the equations. The coefficient matrix is [-5 4 -1; 3 -3 -5; -2 -5 4], and the constant matrix is [11; 17; 0].

Step-by-step explanation:

To set up the matrix for the system of equations:

  • -5x + 4y - z = 11,
  • 3x - 3y - 5z = 17,
  • -2x - 5y + 4z = 0,

We create the coefficient matrix from the left-hand side of the equations and the constant matrix from the right-hand side. The coefficient matrix contains the coefficients of the variables x, y, and z, while the constant matrix contains the constants 11, 17, and 0.

The coefficient matrix is:

[-5 4 -1]

[ 3 -3 -5]

[-2 -5 4]

And the constant matrix or column vector is:

[11]

[17]

[ 0]

This is the standard form for representing a system of linear equations as a matrix equation.

User RobyB
by
7.4k points