Question

18x+5y=88 and x=56+y find the ordered pair

Answer 1

To find the ordered pair for the equations 18x+5y=88 and x=56+y, the substitution method shows that the solution is (16, -40) after following a series of algebraic steps.

Step-by-step explanation:

To find the ordered pair that satisfies both equations 18x+5y=88 and x=56+y, we can use substitution or elimination methods. Since the second equation is already solved for x, we'll use substitution to solve the pair of equations.

Step-by-Step Solution:

1. Write down the given equations:
   
   • 18x + 5y = 88
   • x = 56 + y
2. Substitute the expression for x from the second equation into the first equation:
   
   • 18(56 + y) + 5y = 88
3. Simplify and solve for y:
   
   • 1008 + 18y + 5y = 88
   • 23y = 88 - 1008
   • 23y = -920
   • y = -920 / 23
   • y = -40
4. Substitute y = -40 into the second equation to find x:
   
   • x = 56 + (-40)
   • x = 16
5. The derived ordered pair is (16, -40).