Final answer:
Given the quadratic equation fx=x²+4x+7 , the value of x is (-4 ± √(-12)) / 2 (there are no real solutions to the equation)
Step-by-step explanation:
To solve the quadratic equation fx=x²+4x+7 using the quadratic formula, we need to first identify the values of a, b, and c.
Comparing the given equation to the general form of a quadratic equation, ax²+bx+c=0, we can see that a = 1, b = 4, and c = 7.
Next, we can substitute these values into the quadratic formula, which is x = (-b ± √(b²-4ac)) / (2a).
Plugging in the values, we have:
x = (-4 ± √(4²-4(1)(7))) / (2(1))
Simplifying further:
x = (-4 ± √(16-28)) / 2
x = (-4 ± √(-12)) / 2
Since the square root of a negative number is not a real number, we can conclude that there are no real solutions to the equation. Therefore, the equation fx=x²+4x+7 has no solutions.