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A soccer ball was kicked through the air and it followed the path h(s)=-3s² +75 . Let h(s) represent the height of the soccer ball after s seconds. It will take the soccer ball Response area seconds to hit the ground.

User JayV
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Final answer:

The equation h(s) = -3s² + 75 represents the height of a soccer ball after s seconds. To find the time it takes for the ball to hit the ground, we set h(s) equal to 0 and solve for s. It will take the soccer ball approximately 3.79 seconds to hit the ground.

Step-by-step explanation:

The equation h(s) = -3s² + 75 represents the height of a soccer ball after s seconds. To find the time it takes for the ball to hit the ground, we set h(s) equal to 0 and solve for s.

-3s² + 75 = 0

solving this quadratic equation, we can use the quadratic formula: s = (-b ± √(b² - 4ac)) / (2a).

Using the values from the equation, a = -3, b = 0, and c = 75, we can calculate the values of s.

s₁ = (-0 + √(0² - 4*(-3)*75)) / (2*(-3)) = 3.79 seconds

s₂ = (-0 - √(0² - 4*(-3)*75)) / (2*(-3)) = 0.54 seconds

Since the ball is at a height of 10m at two different times during its trajectory, we take the longer solution for the time it takes the ball to hit the ground. Therefore, it will take the soccer ball approximately 3.79 seconds to hit the ground.

User Franco
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