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Find the horizontal asymptote for the function f(x) = 5x³+6/x²-9x+19

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Final answer:

The horizontal asymptote for the function f(x) = 5x³+6 / x²-9x+19 is y = 5x.

Step-by-step explanation:

To find the horizontal asymptote for the function f(x) = 5x³+6 / x²-9x+19, we need to examine the behavior of the function as x approaches positive infinity and negative infinity.

As x approaches positive infinity, the highest degree term in the numerator and denominator, which are both x³, dominate the function. Therefore, the horizontal asymptote is y = 5x³ / x² = 5x.

Similarly, as x approaches negative infinity, the highest degree term in the numerator and denominator still dominate the function, and the horizontal asymptote is y = 5x³ / x² = 5x.

User Satan Pandeya
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