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For the following equations mi(n)/(m)ax point the range, y=(x-3)²+3

User Addzy K
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Final answer:

To find the range of the equation y = (x-3)²+3, we need to determine the vertex of the parabola formed by the equation. The vertex occurs at (3, 3), which represents the minimum point of the parabola. Therefore, the range is all real numbers greater than or equal to 3.

Step-by-step explanation:

To find the range of the equation y = (x-3)²+3, we first need to understand that the range refers to the set of possible output values of the equation. In this case, the equation represents a quadratic function, which means the range will depend on the vertex of the parabola.

The given equation is in vertex form, which shows that the vertex is located at (3, 3). Since the vertex is the minimum point of the parabola, the range of the equation will be all real numbers greater than or equal to 3. Therefore, the range is [3, ∞).

User Saeed Ur Rehman
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