206k views
0 votes
Mar 12, 9:74:06 PM Find the quotient of 6y^(4)+10y^(3)-8y^(2) divided by 2y.

User Zuri
by
8.9k points

1 Answer

3 votes

Final answer:

To divide the polynomial by 2y, we can use long division. The quotient of 6y^(4) + 10y^(3) - 8y^(2) divided by 2y is 3y^(3) + 5y^(2) - 4y.

Step-by-step explanation:

To divide 6y^(4)+10y^(3)-8y^(2) by 2y, we can use long division.

Starting with the highest exponent, divide 6y^(4) by 2y to get 3y^(3). Multiply 3y^(3) by 2y to get 6y^(4). Subtract 6y^(4) from the original polynomial to get 0.

Next, divide 10y^(3) by 2y to get 5y^(2). Multiply 5y^(2) by 2y to get 10y^(3). Subtract 10y^(3) from the remaining polynomial to get 0.

Finally, divide -8y^(2) by 2y to get -4y. Multiply -4y by 2y to get -8y^(2). Subtract -8y^(2) from the remaining polynomial to get 0.

Therefore, the quotient of 6y^(4)+10y^(3)-8y^(2) divided by 2y is 3y^(3) + 5y^(2) - 4y.

User Dragomirik
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories