Answer:
3.73 mL
Step-by-step explanation:
To solve this problem we can use the equation C₁V₁=C₂V₂, where:
We input the data:
- 6.57 M * V₁ = 0.0490 M * 500 mL
And solve for V₁:
So 3.73 mL of a 6.57 M stock solution would be required to prepare 500 mL of a 0.0490 M solution.