Question

What is the equation of the line that passes through the point (-6,6) and has a
slope of 1/3?

Answer 1

Step-by-step explanation:

y-y = m(x - x)

I couldn't tell if the point was negative, so I'll do both

Positive Negative

(6,6) m= 1/3 -(6,6) m= 1/3

y-6 = 1/3(x - 6) y+6 = 1/3(x +6)

y-6 = 1/3x - 2 y+6 = 1/3x + 2

y = 1/3x +4 y = 1/3x - 4