The graph of the equation is attached with the intercepts at (-5, 0), (0, 10) and (2, 0)
The table of values is
x y
-5 0
0 10
2 0
How to determine the table and the graph of the equation
From the question, we have the following parameters that can be used in our computation:
y = 10 - x² + 3x
This can be expressed as
y = - x² + 3x + 10
The y-intercept of the function is when x = 0
So, we have
y = -0² + 3(0) + 10 = 10
The x-intercept of the function is when y = 0
So, we have
- x² + 3x + 10 = 0
x² - 3x - 10 = 0
This gives
(x - 2)(x + 5) = 0
Evaluate
x = 2 and x = -5
So, we have the following table of values
x y
-5 0
0 10
2 0
The graph is attached
Question
Create a table and graph the equation y = 10 - x² + 3x.
Label its x- and y-intercepts.