141k views
0 votes
What is the resistance of a 150 w lightbulb connected to a 24 v voltage source? type the correct answer in the box. use numerals instead of words. the lightbulb's resistance is ω.

User SaturnsEye
by
8.0k points

2 Answers

2 votes
the resistance of the 150 W lightbulb connected to a 24 V voltage source is approximately 3.84 ohms (Ω).
User Taymless
by
8.5k points
1 vote

Final answer:

The resistance of a 150 W lightbulb connected to a 24 V voltage source is calculated using the formula R = V^2 / P, which yields a resistance of 3.84 Ω.

Step-by-step explanation:

To find the resistance of a 150 W lightbulb that is connected to a 24 V voltage source, we can use the formula P = V^2 / R, which is derived from the power formula P = IV and Ohm's Law V = IR. Here, P is the power in watts, V is the voltage in volts, and R is the resistance in ohms (Ω). To solve for resistance, we rearrange the formula to R = V^2 / P.

Inserting the known values:

R = (24 V)^2 / 150 W = 576 V^2 / 150 W

R = 3.84 Ω

Therefore, the lightbulb's resistance is 3.84 Ω.

User Marigold
by
7.9k points