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What is the energy level of li2 when it is excited to an energy level of n=4? (k=2.18×10–18 j) select the correct answer below: −2.18×10−18 j −3.27×10−18 j −1.23×10−18 j −1.09×10−18 j

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Final answer:

The energy level of Li² when excited to n=4 is -3.27 x 10^-19 J.

Step-by-step explanation:

The energy level of Li² when it is excited to an energy level of n=4 can be calculated using the Bohr model and the formula:



ΔE = -2.18 x 10-18 J * (1/nf2 - 1/ni2)



Plugging in the values, we have:



ΔE = -2.18 x 10-18 J * (1/42 - 1/22) = -2.18 x 10-18 J * (1/16 - 1/4) = -2.18 x 10-18 J * (3/16) = -3.27 x 10-19 J



The correct answer is -3.27 x 10-19 J.

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