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If the molar concentration of the HCl is 0.345 M and there are 40 mL of the solution, what is the initial volume of 1.00 M HCI that it was diluted from

a. 15.0 mL
b. 115.942 mL
c. 13.8 mL
d. 0.008625 mL

User Osanger
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7.8k points

1 Answer

5 votes

Final answer:

To find the initial volume of the 1.00 M HCl solution that was diluted, you can use the formula for dilution: (stock concentration) × (stock volume) = (final concentration) × (final volume). Plugging in the given values and solving, the initial volume is 13.8 mL.

Step-by-step explanation:

To find the initial volume of the 1.00 M HCl solution that was diluted, we can use the formula for dilution:

(stock concentration) × (stock volume) = (final concentration) × (final volume)

Plugging in the values:

(1.00 M) × (stock volume) = (0.345 M) × (40 mL)

Dividing both sides by 1.00 M:

stock volume = (0.345 M) × (40 mL) / 1.00 M

Simplifying the expression:

stock volume = 13.8 mL

Therefore, the initial volume of the 1.00 M HCl solution that was diluted from is 13.8 mL.

User Shalena
by
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