Question

What is the equation of the line through (4, -3) and (0, -2)?

A. y= 4x+ 2
B. y=-4x-2
C.y =-+2
D. y =-- 2

Answer 1

The equation of the line through (4, -3) and (0, -2) is y = (1/4)x - 4.

Step-by-step explanation:

The equation of the line through (4, -3) and (0, -2) can be found using the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.

First, we need to calculate the slope (m) of the line. The slope is given by the formula: m = (y2 - y1) / (x2 - x1). Using the coordinates (4, -3) and (0, -2), we get: m = (-2 - (-3)) / (0 - 4) = 1/4.

Next, we can use one of the given points to find the y-intercept (b). Let's use the point (4, -3): -3 = (1/4)(4) + b -> -3 = 1 + b -> b = -4.

Therefore, the equation of the line through (4, -3) and (0, -2) is y = (1/4)x - 4.