Final answer:
The time in air before striking the ground is 2.33 seconds, the maximum height is 9.15 meters, and the horizontal distance traveled is 31.1 meters.
Step-by-step explanation:
To find the time in air before striking the ground, we can use the formula t = 2v*sin(θ)/g, where v is the initial velocity of the arrow, θ is the angle of launch, and g is the acceleration due to gravity. In this case, v = 20.0 m/s and θ = 25°. Plugging these values into the formula, we get t = 2 * 20.0 * sin(25°) / 9.8 = 2.33 seconds.
The maximum height can be found using the formula h = v^2 * sin^2(θ) / (2 * g). Plugging in the values, we get
h = 20.0^2 * sin^2(25°) / (2 * 9.8)
≈ 9.15 meters.
The horizontal distance traveled can be found using the formula d = v^2 * sin(2θ) / g. Plugging in the values, we get
d = 20.0^2 * sin(2 * 25°) / 9.8
≈ 31.1 meters.