Question

5x=4y+8 and 3x+3y=-3

Answer 1

The solution to the system is
`\(x = -(20)/(7)\)` and
`\(y = -(34)/(7)\)`. This is obtained by eliminating y through equation manipulation, leading to a unique solution.

To solve the system of equations 5x = 4y + 8 and 3x + 3y = -3, we can use the substitution or elimination method. Let's use elimination:

1. Multiply the second equation by 4 to make the coefficients of y in both equations equal:

5x = 4y + 8

12x + 12y = -12

2. Subtract the first equation from the modified second equation to eliminate y:

(12x + 12y) - (5x = 4y + 8)

7x = -20

3. Solve for x:
`x = -(20)/(7)` .

4. Substitute x back into one of the original equations, let's use the first one:

`\[ 5\left(-(20)/(7)\right) = 4y + 8 \]`

5. Solve for y:
`\( y = -(34)/(7) \)`.

So, the solution to the system of equations is
`\(x = -(20)/(7)\)` and

`\(y = -(34)/(7)\).`

Que. Find Linear equations with two unknowns
5x=4y+8 and 3x+3y=-3