Final answer:
To find the second number of the sequence, we calculate the average and then adjust according to the properties of even numbers. The result is that the second number in the sequence is 404646.
Step-by-step explanation:
The question asks us to find the second number in a sequence of 666 consecutive even numbers that sums to 270270270. To approach this problem, let's use the properties of consecutive even numbers and find the average first. The sum of an even number of consecutive even numbers is equal to the average of the first and last number multiplied by the count of numbers. In this case, the average (middle number) times 666 would give us 270270270.
We can find the average by dividing the total sum by the number of terms: 270270270 / 666, which gives us approximately 405975.5. This would be the middle number, not an integer because it's halfway between the two middlemost numbers in our even sequence. Since we're dealing with even numbers, the actual middlemost numbers would be 405974 and 405976. The second number in the sequence will be two more than the first number. Therefore, we need to subtract 665 times 2 from the lower middle number (one less than the count because we're aligning to the first number, not the middle) to find the first number: 405974 - (665*2) = 405974 - 1330 = 404644. Thus, the second number would be 404646.