Final answer:
When resistance in a device connected to a 12 V battery increases, current decreases, power decreases, voltage remains the same, and resistance increases. In a parallel circuit with two resistors, if one resistor's resistance increases, the current through and voltage across the other resistor remain unchanged.
Step-by-step explanation:
When a 12 V battery is connected across a device with variable resistance, the following will occur:
- Current (I): As resistance (R) increases, current will decrease according to Ohm's law (I = V/R), where V is voltage.
- Voltage (V): The voltage across the device will remain unchanged because it is determined by the battery's output of 12 V.
- Power (P): Power will decrease because power is calculated as P = I^2 * R. As current decreases, so does power.
- Resistance (R): By the scenario's definition, resistance is increasing.
For a situation with two identical resistors in parallel, if the resistance of one resistor is increased:
- The current through the unchanged resistor remains the same, and
- The voltage across the unchanged resistor remains the same.
These conclusions arise from the property of parallel circuits where each component receives the full voltage of the source.