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A 3.4-cm -diameter parallel-plate capacitor has a 1.5 mm spacing. the electric field strength inside the capacitor is 1.0×105 v/m .

What is the potential difference across the capacitor?
How much charge is on each plate?

User Michela
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Final answer:

The potential difference across the capacitor is 150 V. To find the charge on each plate, calculate the capacitance using the formula for a parallel-plate capacitor and then multiply by the potential difference.

Step-by-step explanation:

The potential difference across a capacitor is calculated using the formula V = E × d, where V is the potential difference, E is the electric field strength, and d is the separation between the plates. In this case, the electric field strength is 1.0×105 V/m and the spacing is 1.5 mm (0.0015 m). Therefore, the potential difference is V = (1.0×105 V/m) × (0.0015 m) = 150 V.

To find the charge on each plate, we use the capacitance formula Q = C × V. The capacitance C for a parallel-plate capacitor is given by C = ε₀ × (A/d), where A is the area of the plates and ε₀ is the vacuum permittivity (ε₀ = 8.85 × 10⁻¹² F/m). The area A can be calculated from the diameter of the plates (3.4 cm), which is A = π × (0.034 m/2)². After calculating C, multiply by V to get the charge Q on each plate.

User Colde
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