Question

A transparent substance has a refractive index of 1.30. What is the angle of incidence in air when the angle of refraction in the substance is 45 degrees?

Answer 1

The angle of incidence in air when the angle of refraction in the substance is 45 degrees is 22.5 degrees.

Step-by-step explanation:

According to Snell's law, the index of refraction is given by the ratio of the sine of the angle of incidence to the sine of the angle of refraction:

Refractive Index (n) = sin(angle of incidence)/sin(angle of refraction)

In this case, the index of refraction of the substance is given as 1.30 and the angle of refraction is 45 degrees.

We can solve for the angle of incidence by rearranging the formula:

Angle of incidence = sin-1(n * sin(angle of refraction))

Plugging in the values, we get:

Angle of incidence = sin-1(1.30 * sin(45)) = sin-1(1.30 * 0.707) = sin-1(0.919) = 22.5 degrees

Therefore, the angle of incidence in air when the angle of refraction in the substance is 45 degrees is 22.5 degrees.