Question

A cricket ball has a mass of 0.16kg. The ball travels at 30m/s. The ball is hit by a bat with a force of 10800N. After being hit, the ball moves off at 30m/s in the opposite direction. What is the change in momentum of the ball?

1) 0.48 kg·m/s
2) 0.96 kg·m/s
3) 1.92 kg·m/s
4) 3.84 kg·m/s

Answer 1

The change in momentum of the cricket ball, calculated by taking the difference in initial and final momentum (each being 4.8 kg·m/s but in opposite directions), is 9.6 kg·m/s. The magnitude of the change is considered, hence the absolute value is taken. None of the provided options are correct.

Step-by-step explanation:

To calculate the change in momentum of the cricket ball, we use the formula: Δp = m(vf - vi), where Δp is the change in momentum, m is the mass of the ball, vf is the final velocity of the ball, and vi is the initial velocity.

Since the ball is initially moving at 30 m/s and then moves off at 30 m/s in the opposite direction after being hit by the bat, we can calculate the change in momentum as follows:

m vi = 0.16 kg * 30 m/s = 4.8 kg·m/s (initial momentum, positive direction)

m vf = 0.16 kg * (-30 m/s) = -4.8 kg·m/s (final momentum, opposite direction)

Δp = m vf - m vi = (-4.8 kg·m/s) - (4.8 kg·m/s) = -9.6 kg·m/s

Since momentum is a vector and we are interested in the magnitude of the change, we take the absolute value: |Δp| = 9.6 kg·m/s

Therefore, the change in momentum of the ball is 9.6 kg·m/s, which is not one of the options provided. All the given options are incorrect as per our calculations.