220k views
2 votes
What is the maximum ratio of glucose in to glucose out that could theoretically be produced if the energy coupling were 1?

User Thenosic
by
7.8k points

1 Answer

7 votes

Final answer:

The theoretical maximum ratio of glucose in to glucose out for an energy coupling of 1 cannot exceed the maximum ATP yield during aerobic respiration, which is 38 ATP per glucose molecule due to biological inefficiencies.

Step-by-step explanation:

The theoretical maximum ratio of glucose into glucose out with an energy coupling of 1 is equivalent to the efficiency of ATP production during cellular respiration. Considering the complete respiration of a mole of glucose releases about -687 kcal/mol and each ATP synthesis requires approximately 7.3 kcal/mol, we can estimate the maximum amount of ATP that can be produced. If we divide the total energy available by the energy cost per ATP, we get a theoretical yield of about 94 ATP molecules (687 kcal per mole of glucose ÷ 7.3 kcal per mole of ATP). However, in living systems, due to inefficiencies and losses, the actual ATP yield is much lower, with a maximum of 38 ATP per glucose molecule during aerobic respiration.

The maximum ratio of glucose into glucose out, also known as the yield of ATP in aerobic respiration, can be calculated based on the energy output during glucose catabolism. The theoretical maximum yield of ATP through oxidative phosphorylation, the main energy-producing pathway, is approximately 34 ATP per glucose molecule.

In addition, four ATP are produced by substrate-level phosphorylation, resulting in a total maximum yield of 38 ATP per glucose molecule.

User Michael Parkin
by
8.1k points