After the number of wire loops was halved, resulting in the rotation speed being halved to 150 rotations per second, the wire loop completed 1,500 rotations in 10 seconds.
The student initially discovers that the wire loop rotates 300 times every second. When the number of loops is reduced by half, the rotation speed also falls by half, meaning the new rotation speed is 150 times per second. To find the total number of rotations after 10 seconds, we multiply the new rotation speed by the duration, which is:
150 rotations/second × 10 seconds = 1,500 rotations.
Therefore, the correct answer is (c) 1,500 rotations.