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An elevator descends into a mine shaft at the rate of 4 metre perminute. What will be its position after 35 minutes?​

User Jaaq
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1 Answer

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Final answer:

To find the elevator's position after 35 minutes of descending at a rate of 4 meters per minute, multiply the rate by the time, resulting in a position 140 meters below the starting point.

Step-by-step explanation:

If an elevator descends into a mine shaft at the rate of 4 meters per minute, to determine its position after 35 minutes, we simply multiply the rate of descent by the time. The calculation would look like this:

    • Rate of descent = 4 meters/minute
    • Time = 35 minutes
    • Position after 35 minutes = Rate of descent × Time

Therefore, the position after 35 minutes would be 4 meters/minute × 35 minutes = 140 meters.

This means the elevator will be 140 meters below its original starting point after 35 minutes.

User Technicallynick
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