Final answer:
The water absorbed 2509 J of heat energy when it was heated from 25°C to 37°C, calculated using the specific heat of water and the change in temperature.
Step-by-step explanation:
The student asked how much heat energy 50 g of water absorbed when it was heated from 25°C to 37°C. The specific heat of water is given as 4.18 J/g°C, and we can calculate the heat absorbed using the equation q = mcΔT. The mass (m) is 50 g, the specific heat (c) is 4.18 J/g°C, and the change in temperature (ΔT) is 37°C - 25°C, which is 12°C.
To find the heat absorbed, we perform the following calculation:
- q = mcΔT
- q = 50 g * 4.18 J/g°C * 12°C
- q = 2509 J
Therefore, the water absorbed 2509 J of heat energy.